Welcome!

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Hello, Franz Scheerer (Olbers), and welcome to Wikipedia! Thank you for your contributions, especially what you did for Magnetic field. I hope you like the place and decide to stay. Here are a few links to pages you might find helpful:

Please remember to sign your messages on talk pages by typing four tildes (~~~~); this will automatically insert your username and the date. If you need help, check out Wikipedia:Questions, ask me on my talk page, or ask your question on this page and then place {{help me}} before the question. Again, welcome! RockMagnetist (talk) 17:31, 29 October 2013 (UTC)Reply

October 2013

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  Welcome to Wikipedia. We welcome and appreciate your contributions, including your edits to Magnetic field, but we cannot accept original research. Original research also encompasses combining published sources in a way to imply something that none of them explicitly say. Please be prepared to cite a reliable source for all of your contributions. Thank you. RockMagnetist (talk) 17:32, 29 October 2013 (UTC)Reply

Collatz conjecture

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Your edits here, so far, might possibly be suitable for Wikibooks or Wikiversity; they are not suitable here, because there is no source outside of your edits for the material. The (3/2)^k analysis, as I said on the article talk page, might be suitable here if a reputable mathematician stated it. Unfortunately, some of your posts and websites clearly indicate that mathematician is not anyone named "Franz Scheerer". — Arthur Rubin (talk) 14:41, 8 January 2014 (UTC)Reply

Good morning Arthur Rubin, I tried something new. If one start the some number s the numbers n alway can be written as

 

with a,b fractional numbers. If known which operations (3n+1)/2 or n/2 is performed the new a,b can be calculated as follows.

 

Finally a gets the value

 

and as well b

 

Now we can ask wether a cycle occurs

 

or

 

Using   we obtain

 

If the first operation is (3n+1)/2 and the other (3n+1)/2 operations follow directly, we can derive

 

and final get

 

For c=1, l=2 we get s=1.

If the (3n+1)/2 don't follow directly on each other or we don't start with the minimum still

 .

A minimum is, starting with (n/2) divisions

 .

Franz Scheerer (Olbers) (talk) 21:40, 22 January 2014 (UTC)Reply