21:59, 19 January 2007 (UTC)21:59, 19 January 2007 (UTC)21:59, 19 January 2007 (UTC)21:59, 19 January 2007 (UTC)Cleverdan204

Kerrin Thomas












<math>\, K = {{(C)^c (D)^d} \over {(A)^a (B)^b}}