Talk:Semiprime ring

Latest comment: 5 years ago by 130.132.173.59 in topic Alternative definition

Alternative definition edit

If x^2 is in I implies x is in I, then I is semiprime. For if x^k is in I, then x^{2^n} is in I for sufficiently large n, so x is in I.130.132.173.59 (talk) 15:12, 12 September 2018 (UTC)Reply