Talk:Higman–Sims group

Latest comment: 4 years ago by Scott Tillinghast, Houston TX in topic Stabilizer of edge

Presentation edit

Is there any value to having the presentation for HS on this page? It has been copied from the Atlas (http://brauer.maths.qmul.ac.uk/Atlas/spor/HS/) and is hopeless (because completely unmotivated) as a definition. Unless I hear strong objections, I shall remove it.

I have removed it. The previous content was:
HS can also be defined in terms of generators a and b and the following relations:
 
 
 
 
--Huppybanny 09:48, 27 October 2005 (UTC)Reply

Representation edit

The Mathieu group M22 occurs as a maximal subgroup of HS. One permutation matrix representation of M22 fixes a 2-3-3 triangle with vertices (024), (5,123), and (1,5,122). A non-monomial matrix is needed to complete generation of a representation of HS. Scott Tillinghast, Houston TX (talk) 21:28, 21 December 2015 (UTC)Reply

Wilson (2009) gives an example of a Higman-Sims graph within the Leech lattice, permuted by the representation of M22 above:

  • 22 points of shape (1,1,-3,121)
  • 77 points of shape (2,2,26,016)
  • A 100th point (4,4,022)

Differences of adjacent points are of type 3; those of non-adjacent ones are of type 2. Scott Tillinghast, Houston TX (talk) 16:08, 23 December 2015 (UTC)Reply

Problem: find an involution fixing the aforesaid 2-3-3 triangle and transposing all 100 points of the aforesaid graph. What is its trace? Co3 contains involutions of trace 0 but not of trace -8. Scott Tillinghast, Houston TX (talk) 09:07, 29 December 2015 (UTC)Reply

A 2-3-3 triangle? edit

Not if the origin is one vertex. Rather a translation of a 2-3-3 triangle. It would define the same vector space over the rationals as the original triangle, but not the same Z-module. Scott Tillinghast, Houston TX (talk) 15:56, 15 January 2016 (UTC)Reply

Disregard. Scott Tillinghast, Houston TX (talk) 04:02, 25 January 2018 (UTC)Reply

Format problem edit

For some reason my new table of conjugacy classes goes to the end of the page. Scott Tillinghast, Houston TX (talk) 21:25, 24 January 2018 (UTC)Reply

Corrected! Changed |-} to |} at end.

Stabilizer of edge edit

An involution class 2A (trace 8) transposes 40 non-edges, fixes 20 vertices in the Higman-Sims graph.

The stabilizer of an edge includes the group M21 = PSL(3,4), fixing the 100th vertix C and one of the 22 points. It seems the full stabilizer PSL(3,4):2 of that edge is generated by an involution class 2B (trace 0) which would transpose 50 edges. Scott Tillinghast, Houston TX (talk) 05:53, 2 June 2019 (UTC)Reply

I have not found any matrix construction of a 2B involution in the literature. It would exchange the 100th vertex C with one of the 22 points, could exchange the other 21 points with hexads. There would be 56 hexads left over. Scott Tillinghast, Houston TX (talk) 18:14, 2 June 2019 (UTC)Reply

A class 2B matrix gives a bonus: with M23 a representation of Co3. Scott Tillinghast, Houston TX (talk) 22:56, 2 June 2019 (UTC)Reply

An involution class 2A can only transpose non-edges, because it is conjugate to one in the M22 that exchanges hexads only with hexads. A transposed pair of adjacenr (disjoint) hexads would imply a dodecad whose complement includes an octad. Scott Tillinghast, Houston TX (talk) 12:48, 4 June 2019 (UTC)Reply

But Wilson (2009) [p. 213] constructs a monomial class 2B matrix within a representation of the maximal subgroup 24S6, stabilizer of a non-edge. This involution transposes a non-edge. Scott Tillinghast, Houston TX (talk) 03:31, 9 June 2019 (UTC)Reply

The orbits of M21 are 1 (point 1), 1 (100th vertix), 21 (points), 21 (hexads containing point 1), 56 (hyper-ovals). The 2 fixed points form an edge. Magliveras may be wrong that the normalizer M21:2 has orbits 2, 42, 56. Scott Tillinghast, Houston TX (talk) 20:22, 10 June 2019 (UTC)Reply

Perhaps the edge is transposed by an element of order 4. In that case a stabilizer M21.2 would not be a split extension. Scott Tillinghast, Houston TX (talk) 17:10, 16 June 2019 (UTC)Reply