Talk:Equivalent potential temperature
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![]() | This article may be too technical for most readers to understand.(March 2009) |
Mud
editClear as mud:) Lifted adiabatically? to dew point - then squeeze all the water vapor out (how??). Then drop it back down. Does the latent heat of evap stay with it? What is the point of this bit of jargon? Would help to know the use. --Vsmith 15:03, 6 Sep 2004 (UTC)
Also instability is a bit vague. --DavidCary 00:37, 30 November 2005 (UTC)
"R" in this instance is not the universal gas constant, but rather the *specific* gas constant for air. This is the universal gas constant divided by the molar mass of air. changing article to reflect this.
Formula
editHi all, I was just looking at the formula for theta-e and noticed two things:
(1) the link referencing the formula no longer exists (2) is the formula correct and/or have the dimensions been given correctly? Looking at the second term in the first set of brackets, Lv is in kJ/kg and cp in J/(kgK) so is this not a factor of 10^3 out?
Funkytomatoes (talk) 17:58, 31 July 2009 (UTC)
- To answer:
- The link to UCAR is not accessible without an account. Another should be found.
- The formula is correct. You are forgetting that is multiplied by the mixing ratio which in is in grams/Kilograms or kg/kg, cancelling your .
- Pierre cb (talk) 00:14, 1 August 2009 (UTC)
- It ought to be made explicit that mixing ratio here is in grams/Kilograms - if you follow the mixing ratio link, that page expresses it in kg/kg. I also work with model output that gives mixing ratio in kg/kg. I think making the units clear would help.
Explanation for adiabatic temperature change
edit"Some of the internal energy of the parcel is used up in doing the work required to expand against the atmospheric pressure, so the temperature of the parcel drops, even though it has not lost any heat. Conversely, a sinking parcel is compressed and becomes warmer even though no heat is added."
I'm 95% sure this is wrong... the energy isn't used up causing it to drop in temperature. It's an adiabatic change in temperature, the temperature change is because of the difference in pressure caused by rising. Less pressure, lower temperature. I think it may just be badly worded though. — Preceding unsigned comment added by 188.221.226.37 (talk) 21:07, 24 March 2012 (UTC)