Talk:Differentiating Functions
Latest comment: 18 years ago by Admiral Payne in topic Untitled
 | This article was nominated for deletion on 28 October 2005. The result of the discussion was no consensus. |
Untitled edit
Admiral Payne 18:44, 25 October 2005 (UTC)
Okay, I edited the main article's part from f(x+dx)-f(x) -> (x+dx)^n-x^n..
Maybe this needs a little more explaining.
We had f(x+dx)-f(x) for starters. Now we filled this into f(x)=x^n, because this is the main function we want to prove. That would mean; we put (x+dx) and (x) as 'x' into f(x).. Thus leading to:
(x+dx)^n-x^n