Talk:Clipper (electronics)

Latest comment: 1 year ago by PrimeBOT in topic India Education Program course assignment

Necessity for diode in clippers

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Can a clipper operate without a diode of some sort? Careful how you answer this one!--Light current 17:42, 31 March 2006 (UTC)Reply

Why would you not want to use a diode? Anyways, how about an operational amplifier, with a gain of 1, given a limited voltage supply. This would, in effect, clip voltages which are at or exceeds the supply voltage. Ronald Ping Man Chan (talk)

merge

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The following discussion is closed. Please do not modify it. Subsequent comments should be made in a new section.

The result was not to merge clamper (electronics) into clipper (electronics).

I suggest merging clamper (electronics) into clipper (electronics). Some sources draw a distinction between the two. But I they are so closely related that a single article describing both of them, and the subtle distinction between them, would be better than 2 separate article, each of which re-iterate the subtle distinction between them. --68.0.124.33 (talk) 20:37, 13 September 2008 (UTC)Reply

I disagree. Clipper and clampers, while sounding somewhat similar, with both using diodes, are still quite different, I think. The distinction is not subtle. To understand clampers, an understanding of capacitors and how they charge up to remove the dc component is required. For clippers, there is a more simplistic understanding, where the diode either blocks, or shunts. Also, there are different diodes which could be used, for example, zener diodes as voltage references. Compare this with a clamper, which requires a voltage source - zener diode would not work. Ronald Ping Man Chan (talk) 04:52, 10 March 2009 (UTC)Reply

I disagree too.. Clippers Have no energy storage elements unlike clampers. Should not be merged. —Preceding unsigned comment added by San 013 (talkcontribs) 12:59, 12 June 2009 (UTC)Reply

I also disagree, the two articles are different. This would be like merging passive filter and active filter - one could argue that the ae both the same, yet they are clearly different devices with different functions. Seeing as it has been over a year with the general consensus being not to move, I am archiving this discussion and removing the merge templates -- Jack1993jack (talk) 00:15, 14 January 2010 (UTC)Reply

The discussion above is closed. Please do not modify it. Subsequent comments should be made on the appropriate discussion page. No further edits should be made to this discussion.

Image

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Image of clipper circuit requested for shunt and series. Ronald Ping Man Chan (talk) 04:55, 10 March 2009 (UTC)Reply

Image added of shunt voltage clipper using zener diode(s) Jack1993jack (talk) 19:18, 13 January 2010 (UTC)Reply
 

The upper circuit won't work as advertised. The zener diode will conduct if the input is more negative than about 0.7 V. For positive voltages it will open only if the voltage exceeds the rating of the zener. So the resulting waveform will be clipped close to GND with a little shift to the negative. However, the image sugests no negative clipping at all.
Minor glitches: There should be a blob where the vertical diode wire hits the horizontal wire. The vertical axis of the diagrams should point up, not up and down. The horizontal axis should point left. There are no label axis.-----<(kaimartin)>--- (talk) 14:34, 16 December 2010 (UTC)Reply

I agree - The upper circuit won't work as advertised. The zener diode will conduct if the input is more negative than about 0.7 V. For positive voltages it will open only if the voltage exceeds the rating of the zener. So the resulting waveform will be clipped close to GND with a little shift to the negative. However, the image sugests no negative clipping at all. — Preceding unsigned comment added by 146.64.150.246 (talk) 14:01, 16 August 2012 (UTC)Reply

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Square wave analysis

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I have removed the claim in the article that square waves are easier to analyse in clipper circuits. I don't see in what way, any analysis I can think of gives either trivial or useless results. The clipping level is the same for any waveform and is determined by the circuit. The phase onset of clipping is certainly easy to calculate for a square wave - it is clipping at all points of the waveform - but that is hardly telling us anything useful. The most complex thing one might want to calculate for a clipper is to determine the harmonic distortion by Fourier analysis. Well a clipped square wave will still be a square wave so the relative harmonic content will not have changed. We thus come to the conclusion by square wave analysis that a clipper introduces no distortion and is, in fact, an attenuator. SpinningSpark 09:59, 29 January 2014 (UTC)Reply

India Education Program course assignment

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  This article was the subject of an educational assignment supported by Wikipedia Ambassadors through the India Education Program.

The above message was substituted from {{IEP assignment}} by PrimeBOT (talk) on 20:01, 1 February 2023 (UTC)Reply