Hardin Township is located in Pike County, Illinois. As of the 2010 census, its population was 212 and it contained 105 housing units.[2]
Hardin Township | |
|---|---|
Township | |
 Location in Pike County | |
 Pike County's location in Illinois | |
| Country | United States |
| State | Illinois |
| County | Pike |
| Established | November 8, 1853 |
| Area | |
| • Total | 37.41 sq mi (96.9 km2) |
| • Land | 37.39 sq mi (96.8 km2) |
| • Water | 0.03 sq mi (0.08 km2) 0.08% |
| Population (2010) | |
| • Estimate (2016)[1] | 206 |
| • Density | 5.7/sq mi (2.2/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code | 17-149-32863 |
Geography edit
According to the 2010 census, the township encompasses an area of 37.41 square miles (96.9 km2), of which 37.39 square miles (96.8 km2) (or 99.95%) is land and 0.03 square miles (0.078 km2) (or 0.08%) is water.[2]
Demographics edit
| Census | Pop. | Note | %± |
|---|---|---|---|
| 2016 (est.) | 206 | [1] | |
| U.S. Decennial Census[3] | |||
References edit
- ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
- ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
- ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
External links edit
39°31′42″N 90°44′49″W / 39.52833°N 90.74694°W
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