2018 Bengaluru Open – Doubles

Mikhail Elgin and Divij Sharan were the defending champions but chose not to defend their title.

Britons Max Purcell and Luke Saville won the title after defeating Purav Raja and Antonio Šančić 7–6^(7–3), 6–3 in the final.

Seeds edit

First round					Quarterfinals					Semifinals					Final

1	K Krawietz J Nedunchezhiyan	3	6	[7]
	A Martin H Podlipnik Castillo	6	3	[10]		A Martin H Podlipnik Castillo	6	2	[2]
	C-p Hsieh T-h Yang	6	3	[10]		C-p Hsieh T-h Yang	4	6	[10]
	A Nedovyesov M Trungelliti	1	6	[3]							C-p Hsieh T-h Yang	3	4
3	S Balaji V Vardhan	6	6								M Purcell L Saville	6	6
WC	S Nagal B Schnur	4	3		3	S Balaji V Vardhan	6³	3
WC	C Sood L Sood	2	2			M Purcell L Saville	7⁷	6
	M Purcell L Saville	6	6													M Purcell L Saville	7⁷	6
WC	SDP Dev N Kaliyanda Poonacha	1	7⁷	[10]											2	P Raja A Šančić	6³	3
	A Pavlioutchenkov F Peliwo	6	6³	[2]	WC	SDP Dev N Kaliyanda Poonacha	3	6⁵
	A Kadhe S Myneni	6	3	[11]		A Kadhe S Myneni	6	7⁷
4	Sa Ratiwatana So Ratiwatana	3	6	[9]							A Kadhe S Myneni	6	2	[8]
	R Albot M Polmans	4	5							2	P Raja A Šančić	3	6	[10]
	B Kavčič T-S Weissborn	6	7			B Kavčič T-S Weissborn
	R Arneodo Q Halys	4	7⁸	[9]	2	P Raja A Šančić	w/o
2	P Raja A Šančić	6	6⁶	[11]