2017 Monte-Carlo Rolex Masters – Doubles

Pierre-Hugues Herbert and Nicolas Mahut were the defending champions, but lost in the semifinals to Feliciano López and Marc López.

Rohan Bopanna and Pablo Cuevas won the title, defeating López and López in the final, 6–3, 3–6, [10–4].

Seeds edit

All seeds received a bye into the second round.

Semifinals				Final

	Rohan Bopanna Pablo Cuevas	6	6

WC	Romain Arneodo Hugo Nys	4	3
					Rohan Bopanna Pablo Cuevas	6	3	[10]

				7	Feliciano López Marc López	3	6	[4]
7	Feliciano López Marc López	6	7⁷

2	Pierre-Hugues Herbert Nicolas Mahut	1	6⁴

First round					Second round					Quarterfinals					Semifinals

					1	H Kontinen J Peers	6	6
	N Djokovic V Troicki	7	6			N Djokovic V Troicki	3	4
	G Müller G Simon	5	3							1	H Kontinen J Peers	6	3	[11]
	M Matkowski A Peya	3	7⁹	[2]							R Bopanna P Cuevas	3	6	[13]
	R Bopanna P Cuevas	6	6⁷	[10]		R Bopanna P Cuevas	6⁶	6	[10]
					5	R Klaasen R Ram	7⁸	4	[6]
																R Bopanna P Cuevas	6	6
															WC	R Arneodo H Nys	4	3
					3	J Murray B Soares	6	6
	J Benneteau L Pouille	6	4	[8]	PR	T Haas T Huey	3	2
PR	T Haas T Huey	4	6	[10]						3	J Murray B Soares	2	7⁷	[3]
	P Carreño Busta G García López	4	3							WC	R Arneodo H Nys	6	6³	[10]
WC	R Arneodo H Nys	6	6		WC	R Arneodo H Nys	7	7⁷
					8	J-J Rojer H Tecău	5	6²