1998 Romanian Open – Doubles

The 1998 Romanian Open was a men's tennis tournament played on Clay in Bucharest, Romania that was part of the International Series of the 1998 ATP Tour. It was the sixth edition of the tournament and was held from 14 September – 21 September.

Doubles
1998 Romanian Open
Final
ChampionsRomania Andrei Pavel
Romania Gabriel Trifu[1]
Runners-upRomania George Cosac
Romania Dinu Pescariu
Score7–6, 7–6
Events
Singles Doubles
← 1997 · Romanian Open · 1999 →

Seeds

edit

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

Draw

edit

Finals

edit
First round Quarterfinals Semifinals Final[1]
  Á Calatrava
  A Portas
7 6
1   J Alonso
  J Sánchez
6 2   Á Calatrava
  A Portas
3 4
  A Pavel
  G Trifu
6 6   A Pavel
  G Trifu
6 6
  G Castrichella
  F Maggi
1 2   A Pavel
  G Trifu
6 6
4   N Djordjevic
  L Pimek
6 6 4   N Djordjevic
  L Pimek
2 3
  M Calugaru
  R Farcas
4 4 4   N Djordjevic
  L Pimek
5 6 6
  E Benfele Álvarez
  M Puerta
6 6   E Benfele Álvarez
  M Puerta
7 4 1
  A Ilie
  R Sabău
2 4   A Pavel
  G Trifu
7 4 7
  A Sávolt
  T Shimada
6 6   G Cosac
  D Pescariu
6 6 6
  J Apell
  B Karbacher
3 0   A Sávolt
  T Shimada
3 5
  G Cosac
  D Pescariu
6 6   G Cosac
  D Pescariu
6 7
3   K Kinnear
  A Kitinov
1 3   G Cosac
  D Pescariu
5 6 6
  I Moldovan
  A Voinea
6 6 2   T Kempers
  M Oosting
7 2 3
  L Bale
  M Wakefield
4 3   I Moldovan
  A Voinea
1 6 2
2   T Kempers
  M Oosting
6 7 2   T Kempers
  M Oosting
6 4 6
  T Vanhoudt
  F Wibier
1 6

References

edit
  1. ^ a b "1998 Bucharest". International Tennis Federation. Retrieved 4 January 2015.
edit