1968 CONCACAF Champions' Cup

The 1968 CONCACAF Champions' Cup was the 4th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's football club champion in the CONCACAF region.

1968 CONCACAF Champions' Cup
Tournament details
Dates26 May – 1 December 1968
Teams10
Final positions
ChampionsMexico Toluca (1st title)
1967
1969

The tournament was played by 10 teams of 10 nations: Netherlands Antilles, Bermuda, El Salvador, United States, Guatemala, Mexico, Honduras, Suriname, Nicaragua, Costa Rica.

It was played from 26 May till 1 December 1968 under the home/away match system. The tournament was split in 3 zones (North American, Central American and Caribbean), each one qualifying the winner to the final tournament, where the winners of the Central and Caribbean zones played a semi-final to decide who was going to play against the Northern champion in the final. The final was scratched and Toluca were declared champions after both semi-finalists, Aurora and Transvaal, were ejected from the competition (Aurora due to crowd violence and Transvaal for using ineligible players).

Club Deportivo Toluca (actually known as Deportivo Toluca FC) from Mexico thus became for the first time in its history CONCACAF champion.[1][2]

Caribbean zone edit

22 April 1968 1st leg Scherpenheuvel   1–1   Transvaal
TBD   TBD  
2 May 1968 2nd leg Transvaal   3–1   Scherpenheuvel
TBD  
TBD  
TBD  
TBD  
  • Transvaal won 4–2 on aggregate score.

Northern zone edit

First round edit

26 May 1968 1st leg Somerset Trojans   2–1   NY Greek Americans
TBD  
TBD  
TBD  
  • NY Greek Americans won 4–3 on aggregate score.

Second round edit

29 September 1968 1st leg Toluca   4–1   NY Greek Americans Mexico
CST Amaury Epaminondas   14'   85' (pen.)
Felipe Ruvalcaba   25'
Francisco Linares   59'
Tonorezos   33' (pen.)
  • Toluca won 7–3 on aggregate score.

Central American Zone edit

First round edit

Torneo Centroamericano de Concacaf 1968

3 April 1968 1st leg Alajuelense   0–2   Aurora San José, Costa Rica
CST Oscar Molina  
Jorge Roldán  
Stadium: Estadio Nacional de Costa Rica
  • Aurora won 2–1 on aggregate score.
21 April 1968 1st leg Alianza   1–2   Olimpia San Salvador, El Salvador
CST Odir Jacques   Ricardo Taylor  
Donaldo Rosales  
Stadium: Estadio Flor Blanca
28 April 1968 2nd leg Olimpia   1–0   Alianza Tegucigalpa, Honduras
CST Conrado Flores   Stadium: Estadio Nacional Chelato Uclés
  • Olimpia won 3–1 on aggregate score.

Second round edit

3 November 1968 1st leg Olimpia   1–1   Aurora Tegucigalpa, Honduras
CST TBD   TBD   Stadium: Estadio Nacional Chelato Uclés
10 November 1968 2nd leg Aurora   4–0   Olimpia Guatemala City, Guatemala
CST TBD  
TBD  
TBD  
TBD  
Stadium: Estadio Doroteo Guamuch Flores
  • Aurora won 5–1 on aggregate score.

Semi-final edit

27 November 1968 1st leg Transvaal   1–1   Aurora Paramaribo, Dutch Guiana
AST Swie   TBD  
1 December 1968 2nd leg Aurora   0–2   Transvaal Paramaribo, Dutch Guiana
AST Nil TBD  
TBD  

The semi-final was declared null and void, and both teams were ejected from the competition: Aurora after their fans invaded the pitch following the end of the 2nd leg and caused a mass brawl between celebrating Transvaal fans, and Transvaal for using three ineligible players in both legs.

Final edit

After Aurora and Transvaal were both ejected from the competition, the final was scratched and Toluca were declared champions.[1]

Champion edit

 CONCACAF Champions' Cup
1968 champion 
 
Toluca
1st title

References edit

  1. ^ a b Copa de Campeones 1968 on the RSSSF
  2. ^ Todos los campeones de Concacaf on Goal.com, 20 Dec 2020