1966 Texas gubernatorial election

The 1966 Texas gubernatorial election was held on November 8, 1966, to elect the governor of Texas. Incumbent Democratic Governor John Connally was easily reelected to a third term, winning 73% of the vote to Republican T. E. Kennerly's 26%. Connally swept all 254 counties in this election and was inaugurated for his third term on January 17, 1967.

1966 Texas gubernatorial election

← 1964 November 8, 1966 1968 →
 
Nominee John Connally T. E. Kennerly
Party Democratic Republican
Popular vote 1,037,517 368,025
Percentage 72.8% 25.8%

County results
Connally:      50–60%      60–70%      70–80%      80–90%      >90%

Governor before election

John Connally
Democratic

Elected Governor

John Connally
Democratic

The election is, to date, the last time that a candidate for Governor of Texas won more than 70% of the vote, as well as the last in which a candidate won every county. As of 2024, Randall, Ochiltree, and Smith counties have not voted for the Democratic candidate since this election.

Primaries edit

Republican edit

Republican primary results[1]
Party Candidate Votes %
Republican T. E. Kennerly 49,568 100.00%
Total votes 49,568 100.00%

Democratic edit

Democratic primary results
Party Candidate Votes %
Democratic John Connally (incumbent) 932,641 74.29%
Democratic Stanley C. Woods 291,651 23.23%
Democratic Johnnie Mae Hackworthe 31,105 2.48%
Total votes 1,255,400 100.00%

Results edit

General election results
Party Candidate Votes %
Democratic John Connally (incumbent) 1,037,517 72.76%
Republican T. E. Kennerly 368,025 25.81%
Constitution Tommye Gillespie 10,454 0.73%
Conservative Bard Logan 9,810 0.69%
Total votes 1,425,861 100.00%
Democratic hold

References edit

  1. ^ "Texas Almanac". Archived from the original on November 19, 2015. Retrieved August 6, 2015.