1956 Iowa gubernatorial election

The 1956 Iowa gubernatorial election was held on November 6, 1956. Democratic nominee Herschel C. Loveless defeated incumbent Republican Leo Hoegh with 51.22% of the vote.

1956 Iowa gubernatorial election

← 1954 November 6, 1956 1958 →
 
Nominee Herschel C. Loveless Leo Hoegh
Party Democratic Republican
Popular vote 616,852 587,383
Percentage 51.22% 48.78%

County results
Loveless:      50–60%      60–70%
Hoegh:      50–60%      60–70%

Governor before election

Leo Hoegh
Republican

Elected Governor

Herschel C. Loveless
Democratic

Primary elections

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Primary elections were held on June 4, 1956.[1]

Democratic primary

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Candidates

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Results

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Democratic primary results[1]
Party Candidate Votes %
Democratic Herschel C. Loveless 77,206 70.0
Democratic Lawrence E. Plummer 33,103 30.0
Total votes 110,309 100.00

Republican primary

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Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican Leo Hoegh (incumbent) 188,290 100.00
Total votes 188,290 100.00

General election

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Candidates

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  • Herschel C. Loveless, Democratic
  • Leo Hoegh, Republican

Results

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1956 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Democratic Herschel C. Loveless 616,852 51.22%
Republican Leo Hoegh (incumbent) 587,383 48.78%
Majority 29,469
Turnout 1,204,235
Democratic gain from Republican Swing

References

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  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1956. Retrieved March 28, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1956. Retrieved March 28, 2020.