1906 Rhode Island gubernatorial election

The 1906 Rhode Island gubernatorial election was held on November 6, 1906. Democratic nominee James H. Higgins defeated incumbent Republican George H. Utter with 49.92% of the vote.

1906 Rhode Island gubernatorial election

← 1905 November 6, 1906 1907 →
 
Nominee James H. Higgins George H. Utter
Party Democratic Republican
Popular vote 33,195 31,877
Percentage 49.92% 47.94%

Governor before election

George H. Utter
Republican

Elected Governor

James H. Higgins
Democratic

General election edit

Candidates edit

Major party candidates

  • James H. Higgins, Democratic
  • George H. Utter, Republican

Other candidates

  • Bernan E. Helme, Prohibition
  • Warren A. Carpenter, Socialist
  • David J. Moran, Socialist Labor

Results edit

1906 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Democratic James H. Higgins 33,195 49.92%
Republican George H. Utter (incumbent) 31,877 47.94%
Prohibition Bernan E. Helme 714 1.07%
Socialist Warren A. Carpenter 395 0.59%
Socialist Labor David J. Moran 320 0.48%
Majority 1,318
Turnout
Democratic gain from Republican Swing

References edit

  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 10, 2020.