1897 Boston mayoral election

The Boston mayoral election of 1897 occurred on Tuesday, December 21, 1897. In a rematch of the previous election, Democratic incumbent mayor Josiah Quincy defeated Republican former mayor Edwin Upton Curtis to win re-election to a second term. In addition to Curtis, Quincy also defeated two minor challengers.[1]

1897 Boston mayoral election

← 1895 December 21, 1897 1899 →
 
Candidate Josiah Quincy Edwin Upton Curtis
Party Democratic Republican
Popular vote 39,984 35,947
Percentage 50.1% 45.1%

Mayor before election

Josiah Quincy
Democratic

Elected mayor

Josiah Quincy
Democratic

Quincy was inaugurated for his second term on Monday, January 3, 1898.[2]

Candidates

edit

Results

edit
Candidates General Election[5][6]
Votes %
D Josiah Quincy (incumbent) 39,984 50.1%
R Edwin Upton Curtis 35,947 45.1%
BD Thomas Riley 3,000 3.8%
SLP David Goldstein 825 1.0%
all others 7 0.0%

See also

edit

References

edit
  1. ^ "THANKS ALL". The Boston Globe. December 22, 1897. p. 1. Retrieved March 22, 2018 – via pqarchiver.com.
  2. ^ "MAYOR QUINCY'S SECOND INAUGURAL". The Boston Globe. January 4, 1898. p. 6. Retrieved March 22, 2018 – via pqarchiver.com.
  3. ^ "IN THE FRAY". The Boston Globe. November 12, 1897. p. 4. Retrieved March 22, 2018 – via pqarchiver.com.
  4. ^ "RILEY NAMED". The Boston Globe. November 13, 1897. p. 1. Retrieved March 22, 2018 – via pqarchiver.com.
  5. ^ "Boston Mayor Race - Dec 21, 1897". ourcampaigns.com. Retrieved March 22, 2018.
  6. ^ "Annual Report of the Board of Election Commissioners". City of Boston. 1897. p. 47. Retrieved March 22, 2018 – via archive.org. mayoral election results not found

Further reading

edit
edit