1896 Belgian general election

Partial legislative elections were held in Belgium on 5 and 12 July 1896.[1] Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. Only 77 seats out of the 152 seats in the Chamber of Representatives were up for election. The Catholic Party retained their absolute majority.[2]

1896 Belgian general election

← 1894 5 July 1896 1898 →

77 of the 152 seats in the Chamber of Representatives
  First party Second party Third party
 
Leader Paul de Smet de Naeyer N/A
Party Catholic Liberal LiberalSocialist
Seats won 72 1 4
Popular vote 492,541 193,563 49,614
Percentage 49.68% 19.52% 5.00%

Government before election

de Smet de Naeyer I
Catholic

Government after election

de Smet de Naeyer I
Catholic

The Liberal Party, who lost two-thirds of their seats in the previous elections, saw their number of seats decrease further.

Results

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PartyVotes%Seats
Won
Catholic Party492,54149.6872
Liberal Party193,56319.521
Belgian Labour Party150,26015.160
LiberalSocialist kartels49,6145.004
Other parties105,39410.630
Total991,372100.0077
Source: Belgian Elections

References

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  1. ^ Nohlen, Dieter; Stöver, Philip (31 May 2010). Elections in Europe: A data handbook. Nomos Verlagsgesellschaft. p. 289. ISBN 978-3-8329-5609-7.
  2. ^ Nohlen & Stöver, p307