1893 Rhode Island gubernatorial election

The 1893 Rhode Island gubernatorial election was held on April 5, 1893. Incumbent Republican Daniel Russell Brown defeated Democratic nominee David S. Baker with 46.34% of the vote.

1893 Rhode Island gubernatorial election

← 1892 April 5, 1893 1894 →
 
Dem
Nominee Daniel Russell Brown David S. Baker Henry B. Metcalf
Party Republican Democratic Prohibition
Popular vote 21,830 22,015 3,265
Percentage 46.34% 46.73% 6.93%

Governor before election

Daniel Russell Brown
Republican

Elected Governor

Daniel Russell Brown
Republican

General election edit

Candidates edit

Major party candidates

  • Daniel Russell Brown, Republican
  • David S. Baker, Democratic

Other candidates

  • Henry B. Metcalf, Prohibition

Results edit

1893 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Daniel Russell Brown (incumbent) 21,830 46.34%
Democratic David S. Baker 22,015 46.73%
Prohibition Henry B. Metcalf 3,265 6.93%
Majority 185
Turnout
Republican hold Swing

References edit

  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 20, 2020.