1884 Rhode Island gubernatorial election

The 1884 Rhode Island gubernatorial election was held on April 2, 1884. Incumbent Republican Augustus O. Bourn defeated Democratic nominee Thomas W. Segar with 62.39% of the vote.

1884 Rhode Island gubernatorial election

← 1883 April 2, 1884 1885 →
 
Nominee Augustus O. Bourn Thomas W. Segar
Party Republican Democratic
Popular vote 15,936 9,592
Percentage 62.39% 37.56%

Governor before election

Augustus O. Bourn
Republican

Elected Governor

Augustus O. Bourn
Republican

General election edit

Candidates edit

  • Augustus O. Bourn, Republican
  • Thomas W. Segar, Democratic

Results edit

1884 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Augustus O. Bourn (incumbent) 15,936 62.39%
Democratic Thomas W. Segar 9,592 37.56%
Majority 6,344
Turnout
Republican hold Swing

References edit

  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 16, 2020.