1864 United States presidential election in Illinois

The 1864 United States presidential election in Illinois took place on November 8, 1864, as part of the 1864 United States presidential election. Illinois voters chose 16 representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

1864 United States presidential election in Illinois

← 1860 November 8, 1864 1868 →
Turnout20.34% of the total population Increase 0.50 pp[1]
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 16 0
Popular vote 189,512 158,724
Percentage 54.42% 45.58%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

Illinois was won by the National Union candidate incumbent Republican President Abraham Lincoln of Illinois and his running mate former Senator and Military Governor of Tennessee Andrew Johnson. They defeated the Democratic candidate 4th Commanding General of the United States Army George B. McClellan of New Jersey and his running mate Representative George H. Pendleton of Ohio.[2] Lincoln won the state by a margin of 8.84%.

Results

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1864 United States presidential election in Illinois[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
National Union Abraham Lincoln of Illinois Andrew Johnson of Tennessee 189,512 54.42% 16 100.00%
Democratic George B. McClellan of New Jersey George H. Pendleton of Ohio 158,724 45.58% 0 0.00%
Total 348,236 100.00% 16 100.00%

See also

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References

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  1. ^ "1880 Presidential Election Results Illinois Total Population Turnout".
  2. ^ a b c "1864 Presidential Election Results Illinois".