The 1856 United States presidential election in Iowa took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
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 County Results
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Iowa voted for the Republican candidate, John C. Frémont, over Democratic candidate, James Buchanan and American Party candidate Millard Fillmore. Frémont won Iowa by a margin of 8.13%.
Buchanan is the second of only 6 US presidents and the first of 4 Democratic presidents to have never won Iowa.
Results
edit| 1856 United States presidential election in Iowa[1][2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | John C. Frémont of California | William L. Dayton of New Jersey | 45,073 | 48.83% | 4 | 100.00% | ||
| Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 37,568 | 40.70% | 0 | 0.00% | ||
| Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 9,669 | 10.47% | 0 | 0.00% | ||
| Total | 92,310 | 100.00% | 4 | 100.00% | ||||
See also
editReferences
edit- ^ "1856 Presidential General Election Results - Iowa". U.S. Election Atlas. Retrieved December 3, 2017.
- ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.
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