The 1852 United States presidential election in Ohio was held on November 2, 1852, as part of the 1852 United States presidential election. State voters chose 23 electors to the Electoral College, who voted for President and Vice President.
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Ohio was narrowly won by the Democratic Party candidate, Franklin Pierce, who won the state with a plurality of 47.83 percent of the popular vote. The Whig Party candidate, Winfield Scott, garnered 43.18 percent of the popular vote, and Free Soil Party candidate John P. Hale gained 8.98 percent,[1] a figure exceeded by a third-party candidate in Ohio only six times since.[a]
Pierce would become the final Democrat to win Ohio until Woodrow Wilson won it in 1912.
Results
edit1852 United States presidential election in Ohio | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Franklin Pierce | 168,933 | 47.83% | 23 | |
Whig | Winfield Scott | 152,523 | 43.18% | 0 | |
Free Soil | John P. Hale | 31,732 | 8.98% | 0 | |
Totals | 353,188 | 100.0% | 23 |
See also
editNotes
edit- ^ In 1912, both Theodore Roosevelt and Eugene V. Debs exceeded Hale’s share, as did Robert M. La Follette in 1924, George Wallace in 1968, and Ross Perot in both 1992 and 1996.[2]
References
edit- ^ "1852 Presidential General Election Results – Ohio". Dave Leip’s U.S. Election Atlas.
- ^ "Presidential General Election Results Comparison – Ohio". Dave Leip’s U.S. Election Atlas.