The 1844 United States presidential election in New Jersey took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
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County Results
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New Jersey voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won New Jersey by a margin of 1.09 percent; however, Polk would be the last Democrat to carry Cape May County until Woodrow Wilson in 1912.[1] This is the last time a Democrat won without carrying Hudson County.
Results
edit1844 United States presidential election in New Jersey[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 38,318 | 50.46% | 7 | 100.00% | ||
Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 37,495 | 49.37% | 0 | 0.00% | ||
Liberty | James G. Birney of Michigan | Thomas Morris of Ohio | 131 | 0.17% | 0 | 0.00% | ||
Total | 75,944 | 100.00% | 7 | 100.00% |
See also
editReferences
edit- ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 258-259 ISBN 0786422173
- ^ "1844 Presidential General Election Results – New Jersey". U.S. Election Atlas. Retrieved December 23, 2013.