1816 Delaware gubernatorial election

The 1816 Delaware gubernatorial election was held on October 1, 1816. Incumbent Federalist Governor Daniel Rodney was unable to seek re-election due to term limits. Former State Representative John Clark ran as the Federalist nominee, and narrowly defeated Democratic-Republican nominee Manaen Bull to hold the office for his party.[1]

1816 Delaware gubernatorial election

← 1813 October 1, 1816 1819 →
 
Nominee John Clark Manaen Bull
Party Federalist Democratic-Republican
Popular vote 4,008 3,517
Percentage 53.26% 46.74%

Governor before election

Daniel Rodney
Federalist

Elected Governor

John Clark
Federalist

General election edit

Results edit

1816 Delaware gubernatorial election[2]
Party Candidate Votes % ±%
Federalist John Clark 4,008 53.26% -1.94%
Democratic-Republican Manaen Bull 3,517 46.74% +1.94%
Majority 491 6.52% -3.88%
Turnout 7,525 100.00%
Federalist hold

References edit

  1. ^ Conrad, Henry C. (1908). History of the State of Delaware: From the Earliest Settlements to the Year 1907. Vol. 1. Lancaster, Pa.: Wickersham Company, Printers and Binders. p. 175.
  2. ^ "Delaware 1816 Governor". A New Nation Votes: American Election Returns 1787-1825. Tufts University. Retrieved June 17, 2021.

Bibliography edit

  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.