1808 United States presidential election in Kentucky

The 1808 United States presidential election in Kentucky took place between 4 November and 7 December 1808, as part of the 1808 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

1808 United States presidential election in Kentucky
← 1804 4 November – 7 December 1808 1812 →
 
Nominee James Madison Charles C. Pinckney
Party Democratic-Republican Federalist
Home state Virginia South Carolina
Running mate George Clinton Rufus King
Electoral vote 7 0
Popular vote 2,679 54
Percentage 98.02% 1.98%

Kentucky cast seven electoral votes, as one elector didn't vote, for the Democratic-Republican candidate James Madison over the Federalist candidate Charles C. Pinckney. The electoral votes for Vice president were cast for Madison's running mate George Clinton from New York. The state was divided into two electoral districts with four electors each, whereupon each district's voters chose the electors.[2]

Results

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1808 United States presidential election in Kentucky[3]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Madison 2,679 98.02% 7
Federalist Charles C. Pinckney 54 1.98% 0
None Not Cast 1
Totals 2,733 100.0% 8

See also

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References

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  1. ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 14, 2023.
  2. ^ "1808 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
  3. ^ "1808 Presidential Election". 270towin.com. Retrieved July 14, 2023.