This article relies largely or entirely on a single source. (July 2023) |
The 1804 United States presidential election in Massachusetts took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. Voters chose 17 representatives, or electors to the Electoral College, who voted for president and Vice President.
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During this election, the Federalist Party continued to lose ground as incumbent president Thomas Jefferson won all 17 Massachusetts state electors by a narrow margin of 7.16%. Jefferson would end up as the winner of the 1804 United States presidential election in a landslide victory.
Results edit
1804 United States presidential election in Massachusetts[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Thomas Jefferson (incumbent) | 29,599 | 53.58% | 17 | |
Federalist | Charles C. Pinckney | 25,644 | 46.42% | 0 | |
Totals | 55,243 | 100.0% | 17 |
1804 Vice Presidential Electoral Vote[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Electoral votes | |||
Democratic-Republican | George Clinton (incumbent) | 17 | |||
Federalist | Rufus King | 0 | |||
Totals | 17 |
See also edit
References edit
- ^ a b "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 4, 2023.