1884 United States presidential election in Minnesota

The 1884 United States presidential election in Minnesota took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

1884 United States presidential election in Minnesota

← 1880 November 4, 1884 1888 →
 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 7 0
Popular vote 111,865 70,065
Percentage 58.78% 36.87%

County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

Minnesota was won by Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 21.91%.

With 58.78% of the popular vote, Minnesota would prove to be Blaine's second strongest victory in terms of percentage in the popular vote after Vermont.[1]

As of 2020, this remains the last time that a Republican presidential nominee would win a majority of the vote in Minnesota while losing nationally.

Results

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1884 United States presidential election in Minnesota[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 111,685 58.78% 7 100.00%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 70,065 36.87% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 4,684 2.47% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 3,583 1.89% 0 0.00%
Total 190,017 100.00% 7 100.00%

See also

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References

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  1. ^ "1884 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1884 Presidential General Election Results - Minnesota". U.S. Election Atlas. Retrieved December 23, 2013.