1940 United States Senate election in Vermont

The 1940 United States Senate election in Vermont took place on November 5, 1940. Incumbent Republican Warren Austin successfully ran for re-election to another term in the United States Senate, defeating Democratic candidate Ona S. Searles. Austin would resign in August 1946 to become United States Ambassador to the United Nations; Ralph Flanders was appointed to replace him and went on to win election to a full term in 1946.

1940 United States Senate election in Vermont

← 1934 November 5, 1940 (1940-11-05) 1946 →
 
Nominee Warren Austin Ona Searles
Party Republican Democratic
Popular vote 93,283 47,101
Percentage 66.45% 33.55%


Austin:      50-60%      60-70%      70-80%      80-90%      90-100%
Searles:      50-60%      60-70%      80-90%

U.S. senator before election

Warren Austin
Republican

Elected U.S. Senator

Warren Austin
Republican

Republican primary

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Candidates

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Results

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1940 Republican Senate primary[1]
Party Candidate Votes %
Republican Warren Austin (incumbent) 60,603 99.89%
Write-in 65 0.11%
Total votes 60,668 100.00%

Democratic primary

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Candidates

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Results

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1940 Democratic Senate primary[1]
Party Candidate Votes %
Democratic Ona S. Searles 5,340 99.39%
Write-in 33 0.61%
Total votes 5,373 100.00%

General election

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Results

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United States Senate election in Vermont, 1940[2]
Party Candidate Votes % ±%
Republican Warren Austin (inc.) 93,283 66.45%  15.41
Democratic Ona S. Searles 47,101 33.55%  15.41
Total votes 140,384 100.00%

See also

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References

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  1. ^ a b "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on June 17, 2015. Retrieved June 16, 2015.
  2. ^ "General Election Results - U.S. Senator - 1914-2014" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on March 4, 2016. Retrieved June 16, 2015.