1818 United States Senate election in Pennsylvania
(Redirected from United States Senate election in Pennsylvania, 1818)
The 1818 United States Senate election in Pennsylvania was held on December 8, 1818. Walter Lowrie was elected by the Pennsylvania General Assembly to the United States Senate.[1]
Results
editIncumbent Democratic-Republican Abner Lacock, who was elected in 1812, was not a candidate for re-election to another term. The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on December 8, 1818, to elect a new Senator to fill the term beginning on March 4, 1819. The results of the vote of both houses combined are as follows:
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic-Republican | Walter Lowrie | 87 | 67.97 | |
Democratic-Republican | Isaac Weaver | 32 | 25.00 | |
Democratic-Republican | John Tod | 1 | 0.78 | |
N/A | Not voting | 8 | 6.25 | |
Totals | 128 | 100.00% |
References
edit- ^ a b "U.S. Senate Election - 8 December 1818" (PDF). Wilkes University. Retrieved December 22, 2013.