Template talk:Tenacious D

Latest comment: 17 years ago by Digitaltam in topic Lee

Lee

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Lee, as the unofficial third man in the band belongs on this template directly below JB and KG. Milchama 16:55, 19 December 2006 (UTC)Reply

Lee is the only person in this whole Tenacious D group that is a fictional character portrayed by an actor. Sure JB and KG are characters on their own, but that's their real names. I made the JR Reed article, but I think I separate Lee one should be made as well. Milchama 02:02, 20 December 2006 (UTC)Reply
I don't think that he deserves two articles. Just use one article to talk about the real JR Reed and the fictional Lee. Joltman 11:45, 20 December 2006 (UTC)Reply
Lee and JR Reed are not the same person, one is a character and one is the actor who portrays Lee. One (bigger) example is separate articles for Jerry Seinfeld and Jerry Seinfeld (character). Since both of them are a big part of the D, they should both be on the template. Milchama 12:03, 20 December 2006 (UTC)Reply
However Seinfeld and his character are far more notable than Lee/JR Reed. I'm talking in terms of Wikipedia's scope as to what should get an article. Joltman 13:03, 20 December 2006 (UTC)Reply
Lee never performed on any of the albums. Yes, a song referred to his character but that is all. I think your like of the D is making you biased. — Preceding unsigned comment added by 81.157.159.112 (talkcontribs) 14:10, 20 December 2006
Just because he doesn't perform on an album doesn't mean he can't be on the template. He is still very much associated with the band. Joltman 14:38, 20 December 2006 (UTC)Reply

Can "81.157.159.112" please stop deleting Lee from the template? Right now, the general consensus is to keep him on the template. Milchama 17:38, 20 December 2006 (UTC)Reply

I'll stop reverting it now that the weight of opinion is against me but, we all here seem to know some stuff about the D, so, if I was to make an entry in the main Tenacious D page, would you help me with it?

Digitaltam 14:23, 21 December 2006 (UTC)Reply