File:Amanullah Khan with Paul von Hindenburg 1928.jpg

Summary edit

Fair use for Amanullah_Khan edit

Though this image is subject to copyright, its use is covered by the U.S. fair use laws because:

   # It is a historically significant photo of a famous individual.
   # It is of much lower resolution than the original (copies made from it will be of very inferior quality).
   # The photo is only being used for informational purposes.
   # Its inclusion in the article adds significantly to the article because the photo and its historical significance are the object of discussion in the article.

Licensing edit

This photograph is copyrighted and is NOT under a free license. However, it is believed that the use of this work: to provide visual identification of one or more specific individual(s), or an identifiable gathering of them, where the individual(s) concerned are deceased, or where access would for practical purposes be impossible, and for whom there is no known representation under a 'free' license, on the English-language Wikipedia, hosted on servers in the United States by the non-profit Wikimedia Foundation, qualifies as fair use under United States copyright law. Any other uses of this image, on Wikipedia or elsewhere, may be copyright infringement. See Wikipedia:Non-free content and Wikipedia:Copyrights. Fair use //en.wikipedia.org/wiki/File:Amanullah_Khan_with_Paul_von_Hindenburg_1928.jpg true

To the uploader: Please add a detailed non-free use rationale for each article the image is used in, which must also declare compliance with the other parts of the non-free content criteria, as well as the source of the work and copyright information. For example non-free use rationales, see Wikipedia:Use rationale examples. Template:Non-free use rationale biog may be helpful for stating the rationale. This tag should only be used for biographical images, typically those used to identify the subject. To patrollers and administrators: If this image has an appropriate rationale please append |image has rationale=yes as a parameter to the license template.