1998 Kremlin Cup – Women's doubles

Arantxa Sánchez-Vicario and Natasha Zvereva were the defending champions but only Zvereva competed that year with Mary Pierce.

Women's doubles
1998 Kremlin Cup
1997 ChampionsSpain Arantxa Sánchez Vicario
Belarus Natasha Zvereva
Final
ChampionsFrance Mary Pierce
Belarus Natasha Zvereva
Runners-upUnited States Lisa Raymond
Australia Rennae Stubbs
Score6–3, 6–4
Details
Seeds4
Events
Singles men women
Doubles men women
← 1997 · Kremlin Cup · 1999 →

Pierce and Zvereva won in the final 6–3, 6–4 against Lisa Raymond and Rennae Stubbs.

Seeds

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Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1.   Lisa Raymond /   Rennae Stubbs (final)
  2.   Conchita Martínez /   Patricia Tarabini (quarterfinals)
  3.   Katrina Adams /   Larisa Neiland (first round)
  4.   Elena Likhovtseva /   Ai Sugiyama (first round)

Draw

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First round Quarterfinals Semifinals Final
1   L Raymond
  R Stubbs
6 6  
    I Spîrlea
  C Vis
0 3   1   L Raymond
  R Stubbs
6 6  
    M Bollegraf
  E Tatarkova
6 6       M Bollegraf
  E Tatarkova
3 2  
    S Appelmans
  A Huber
3 0   1   L Raymond
  R Stubbs
6 7  
3   K Adams
  L Neiland
3 3   Q   C Black
  I Selyutina
3 5  
Q   C Black
  I Selyutina
6 6   Q   C Black
  I Selyutina
6 6  
    J Halard-Decugis
  C Rubin
4 0 r     C Cristea
  C Morariu
4 0  
    C Cristea
  C Morariu
6 1   1   Lisa Raymond
  Rennae Stubbs
3 4  
    A Kournikova
  M Seles
6 3 6     Mary Pierce
  Natasha Zvereva
6 6  
    B Schett
  P Schnyder
4 6 3     A Kournikova
  M Seles
w/o    
    S Williams
  V Williams
3 7 7     S Williams
  V Williams
     
4   E Likhovtseva
  A Sugiyama
6 5 6     A Kournikova
  M Seles
4 1  
WC   E Makarova
  N Petrova
0 6       M Pierce
  N Zvereva
6 6  
    M Pierce
  N Zvereva
6 7       M Pierce
  N Zvereva
6 6  
    S Farina
  K Habšudová
4 4   2   C Martínez
  P Tarabini
2 2  
2   C Martínez
  P Tarabini
6 6  
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